If the maximum Zs for a circuit is 1.85 ohms and the R1+R2 is 1.03 ohms, what is Ze?

To determine the value of Ze in the context given, we can use the relationship between Zs, R1, R2, and Ze.

Zs represents the total earth fault loop impedance, which includes the resistance of the supply conductors and the earth electrode resistance. The formula used is:

[ Z_s = R_1 + R_2 + Z_e ]

Where R1 is the resistance of the phase conductor, R2 is the resistance of the earth conductor, and Ze is the earth fault loop impedance at the origin of the circuit. Given that Zs is 1.85 ohms and R1 + R2 is 1.03 ohms, we can rearrange the formula to solve for Ze:

[ Z_e = Z_s - (R_1 + R_2) ]

Substituting the known values:

[ Z_e = 1.85 , \text{ohms} - 1.03 , \text{ohms} ]

[ Z_e = 0.82 , \text{ohms} ]

Thus, this calculation shows that the value of Ze is indeed 0.82 ohms, confirming that the correct answer to the question is